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5y^2+10y=14y-5
We move all terms to the left:
5y^2+10y-(14y-5)=0
We get rid of parentheses
5y^2+10y-14y+5=0
We add all the numbers together, and all the variables
5y^2-4y+5=0
a = 5; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·5·5
Δ = -84
Delta is less than zero, so there is no solution for the equation
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